scipy.sparse.linalg._dsolve._superlu:gstrs

Summary

solves the linear system A*x = b via backward and forward substitution, with either A=L*U, A=(L*U)^T, or A=conj(L*U)^T. trans says whether the matrix is transposed ("T"), conjugate transposed ("H"), or normal ("N"). L is specified in the compressed sparse column format via parameters N,nnz,nzvals,rowind,colptr. U is specified in the compressed sparse column format via parameters N,nnz,nzvals,rowind,colptr. b is specified as a dense vector.