bundles / scipy 2.0.0.dev0+git20260907.41eeb59 / scipy / sparse / linalg / _isolve / iterative / bicgstab
function
scipy.sparse.linalg._isolve.iterative:bicgstab
source: build-install/usr/lib/python3.14/site-packages/scipy/sparse/linalg/_isolve/iterative.py:160
Signature
def bicgstab(A, b, x0 = None, *, rtol = 1e-05, atol = 0.0, maxiter = None, M = None, callback = None)Summary
Solve Ax = b with the BIConjugate Gradient STABilized method.
Parameters
A: {sparse array, ndarray, LinearOperator}The real or complex N-by-N matrix of the linear system. Alternatively,
Acan be a linear operator which can produceAxandA^T xusing, e.g.,scipy.sparse.linalg.LinearOperator.b: ndarrayRight hand side of the linear system. Has shape (N,) or (N,1).
x0: ndarrayStarting guess for the solution.
rtol, atol: float, optionalParameters for the convergence test. For convergence,
norm(b - A @ x) <= max(rtol*norm(b), atol)should be satisfied. The default isatol=0.andrtol=1e-5.maxiter: intMaximum number of iterations. Iteration will stop after maxiter steps even if the specified tolerance has not been achieved.
M: {sparse array, ndarray, LinearOperator}Preconditioner for
A. It should approximate the inverse ofA(see Notes). Effective preconditioning dramatically improves the rate of convergence, which implies that fewer iterations are needed to reach a given error tolerance.callback: functionUser-supplied function to call after each iteration. It is called as
callback(xk), wherexkis the current solution vector.
Returns
x: ndarrayThe converged solution.
info: intProvides convergence information:
0successful exit >0 : convergence to tolerance not achieved, number of iterations <0 : parameter breakdown
Notes
The preconditioner M should be a matrix such that M @ A has a smaller condition number than A, see [1] .
Examples
import numpy as np from scipy.sparse import csc_array from scipy.sparse.linalg import bicgstab R = np.array([[4, 2, 0, 1], [3, 0, 0, 2], [0, 1, 1, 1], [0, 2, 1, 0]]) A = csc_array(R) b = np.array([-1, -0.5, -1, 2]) x, exit_code = bicgstab(A, b, atol=1e-5) print(exit_code) # 0 indicates successful convergence np.allclose(A.dot(x), b)✓
True
Aliases
scipy.sparse.linalg.bicgstab