numpy:isclose

Notes

For finite values, isclose uses the following equation to test whether two floating point values are equivalent.

absolute(a - b) <= (atol + rtol * absolute(b))

Unlike the built-in math.isclose, the above equation is not symmetric in a and b -- it assumes b is the reference value -- so that isclose(a, b) might be different from isclose(b, a).

The default value of atol is not appropriate when the reference value b has magnitude smaller than one. For example, it is unlikely that a = 1e-9 and b = 2e-9 should be considered "close", yet isclose(1e-9, 2e-9) is True with default settings. Be sure to select atol for the use case at hand, especially for defining the threshold below which a non-zero value in a will be considered "close" to a very small or zero value in b.

isclose is not defined for non-numeric data types. bool is considered a numeric data-type for this purpose.