bundles / scipy latest / scipy / linalg / _decomp_svd / null_space
function
scipy.linalg._decomp_svd:null_space
source: build-install/usr/lib/python3.14/site-packages/scipy/linalg/_decomp_svd.py:411
Signature
def null_space(A, rcond = None, *, overwrite_a = False, check_finite = True, lapack_driver = gesdd)Summary
Construct an orthonormal basis for the null space of A using SVD.
Extended Summary
The documentation is written assuming array arguments are of specified "core" shapes. However, array argument(s) of this function may have additional "batch" dimensions prepended to the core shape. In this case, the array is treated as a batch of lower-dimensional slices; see linalg_batch for details. The NEP 5 signature of this function is (m,n)->(n,n).
Parameters
A: (M, N) array_likeInput array
rcond: float, optionalRelative condition number. Singular values
ssmaller thanrcond * max(s)are considered zero. Default: floating point eps * max(M,N).overwrite_a: bool, optionalWhether to overwrite
a; may improve performance. Default is False. See tutorial_linalg_overwrite for details.check_finite: bool, optionalWhether to check that the input matrix contains only finite numbers. Disabling may give a performance gain, but may result in problems (crashes, non-termination) if the inputs do contain infinities or NaNs.
lapack_driver: {'gesdd', 'gesvd'}, optionalWhether to use the more efficient divide-and-conquer approach (
'gesdd') or general rectangular approach ('gesvd') to compute the SVD. MATLAB and Octave use the'gesvd'approach. Default is'gesdd'.
Returns
Z: (N, K) ndarrayOrthonormal basis for the null space of A. K = dimension of effective null space, as determined by rcond
Examples
1-D null space:import numpy as np from scipy.linalg import null_space A = np.array([[1, 1], [1, 1]]) ns = null_space(A)✓
ns * np.copysign(1, ns[0,0]) # Remove the sign ambiguity of the vector
✗array([[ 0.71],
[-0.71]])
2-D null space:
from numpy.random import default_rng rng = default_rng() B = rng.random((3, 5)) Z = null_space(B) Z.shape np.allclose(B.dot(Z), 0)✓
TrueThe basis vectors are orthonormal (up to rounding error):
Z.T.dot(Z)
✗array([[1., 0.],
[0., 1.]])
See also
Aliases
scipy.linalg.null_space