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bundles / numpy 2.4.3 / numpy / ma / core / allclose

function

numpy.ma.core:allclose

source: /numpy/ma/core.py :8446

Signature

def   allclose ( a b masked_equal = True rtol = 1e-05 atol = 1e-08 )

Summary

Returns True if two arrays are element-wise equal within a tolerance.

Extended Summary

This function is equivalent to allclose except that masked values are treated as equal (default) or unequal, depending on the masked_equal argument.

Parameters

a, b : array_like

Input arrays to compare.

masked_equal : bool, optional

Whether masked values in a and b are considered equal (True) or not (False). They are considered equal by default.

rtol : float, optional

Relative tolerance. The relative difference is equal to rtol * b. Default is 1e-5.

atol : float, optional

Absolute tolerance. The absolute difference is equal to atol. Default is 1e-8.

Returns

y : bool

Returns True if the two arrays are equal within the given tolerance, False otherwise. If either array contains NaN, then False is returned.

Notes

If the following equation is element-wise True, then allclose returns True

absolute(`a` - `b`) <= (`atol` + `rtol` * absolute(`b`))

Return True if all elements of a and b are equal subject to given tolerances.

Examples

import numpy as np
a = np.ma.array([1e10, 1e-7, 42.0], mask=[0, 0, 1])
a
b = np.ma.array([1e10, 1e-8, -42.0], mask=[0, 0, 1])
np.ma.allclose(a, b)
a = np.ma.array([1e10, 1e-8, 42.0], mask=[0, 0, 1])
b = np.ma.array([1.00001e10, 1e-9, -42.0], mask=[0, 0, 1])
np.ma.allclose(a, b)
np.ma.allclose(a, b, masked_equal=False)
Masked values are not compared directly.
a = np.ma.array([1e10, 1e-8, 42.0], mask=[0, 0, 1])
b = np.ma.array([1.00001e10, 1e-9, 42.0], mask=[0, 0, 1])
np.ma.allclose(a, b)
np.ma.allclose(a, b, masked_equal=False)

See also

all
any
numpy.allclose

the non-masked allclose.

Aliases

  • numpy.ma.allclose