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bundles / numpy 2.5.0.dev0+git20251130.2de293a / numpy / intersect1d

_ArrayFunctionDispatcher

numpy:intersect1d

source: /dev/numpy/build-install/usr/lib/python3.14/site-packages/numpy/lib/_arraysetops_impl.py :666

Signature

def   intersect1d ( ar1 ar2 assume_unique = False return_indices = False )

Summary

Find the intersection of two arrays.

Extended Summary

Return the sorted, unique values that are in both of the input arrays.

Parameters

ar1, ar2 : array_like

Input arrays. Will be flattened if not already 1D.

assume_unique : bool

If True, the input arrays are both assumed to be unique, which can speed up the calculation. If True but ar1 or ar2 are not unique, incorrect results and out-of-bounds indices could result. Default is False.

return_indices : bool

If True, the indices which correspond to the intersection of the two arrays are returned. The first instance of a value is used if there are multiple. Default is False.

Returns

intersect1d : ndarray

Sorted 1D array of common and unique elements.

comm1 : ndarray

The indices of the first occurrences of the common values in ar1. Only provided if return_indices is True.

comm2 : ndarray

The indices of the first occurrences of the common values in ar2. Only provided if return_indices is True.

Examples

import numpy as np
np.intersect1d([1, 3, 4, 3], [3, 1, 2, 1])
To intersect more than two arrays, use functools.reduce:
from functools import reduce
reduce(np.intersect1d, ([1, 3, 4, 3], [3, 1, 2, 1], [6, 3, 4, 2]))
To return the indices of the values common to the input arrays along with the intersected values:
x = np.array([1, 1, 2, 3, 4])
y = np.array([2, 1, 4, 6])
xy, x_ind, y_ind = np.intersect1d(x, y, return_indices=True)
x_ind, y_ind
xy, x[x_ind], y[y_ind]

Aliases

  • numpy.intersect1d