This is a pre-release version (latest).Go to latest (1.18.0)
{ } Raw JSON

bundles / scipy latest / scipy / signal / _signaltools / invresz

function

scipy.signal._signaltools:invresz

source: build-install/usr/lib/python3.14/site-packages/scipy/signal/_signaltools.py:3592

Signature

def invresz(r, p, k, tol = 0.001, rtype = avg)

Summary

Compute b(z) and a(z) from partial fraction expansion.

Extended Summary

If M is the degree of numerator b and N the degree of denominator a:

        b(z)     b[0] + b[1] z**(-1) + ... + b[M] z**(-M)
H(z) = ------ = ------------------------------------------
        a(z)     a[0] + a[1] z**(-1) + ... + a[N] z**(-N)

then the partial-fraction expansion H(z) is defined as

        r[0]                   r[-1]
= --------------- + ... + ---------------- + k[0] + k[1]z**(-1) ...
  (1-p[0]z**(-1))         (1-p[-1]z**(-1))

If there are any repeated roots (closer than tol), then the partial fraction expansion has terms like

     r[i]              r[i+1]                    r[i+n-1]
-------------- + ------------------ + ... + ------------------
(1-p[i]z**(-1))  (1-p[i]z**(-1))**2         (1-p[i]z**(-1))**n

This function is used for polynomials in negative powers of z, such as digital filters in DSP. For positive powers, use invres.

Parameters

r : array_like

Residues corresponding to the poles. For repeated poles, the residues must be ordered to correspond to ascending by power fractions.

p : array_like

Poles. Equal poles must be adjacent.

k : array_like

Coefficients of the direct polynomial term.

tol : float, optional

The tolerance for two roots to be considered equal in terms of the distance between them. Default is 1e-3. See unique_roots for further details.

rtype : {'avg', 'min', 'max'}, optional

Method for computing a root to represent a group of identical roots. Default is 'avg'. See unique_roots for further details.

Returns

b : ndarray

Numerator polynomial coefficients.

a : ndarray

Denominator polynomial coefficients.

Examples

The following example builds b(z) / a(z) back from its partial-fraction expansion:
import numpy as np
from scipy import signal
r = np.array([-2.2, 3.2])
p = np.array([0.25, 0.5])
k = np.array([])
b, a = signal.invresz(r, p, k)
b
a
✓
array([ 1.   , -0.75 ,  0.125])
Use `residuez` to get back the expansion:
signal.residuez(b, a)
✓
(array([-2.2,  3.2]), array([0.25, 0.5 ]), array([], dtype=float64))
A non-empty `k` adds the direct term:
r = np.array([0.4])
p = np.array([0.5])
k = np.array([1.6, -0.2])
b, a = signal.invresz(r, p, k)
b, a
✓
(array([ 2. , -1. ,  0.1]), array([ 1. , -0.5]))

See also

invres
residuez
unique_roots

Aliases

  • scipy.signal.invresz